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How can i plot graph without getting long result answer of inexact coffecient?

February 5, 2019   BI News and Info
 How can i plot graph without getting long result answer of inexact coffecient?

wn = 100;
aap = 0.2;
ome = 9;
Solve[{(2 x + 2) ((dco – wnaa px)^2 + 1) + 4*ome*x == 0}, {x}]
Plot[{x /. %}, {dco, -40, 0}]

i am using this code and getting the right graph. but the Problem is that i do not want the result in this form as it is showing like this-
{{x -> 0.0333333 (-10. + dco) + ((0.0000208333 –
0.0000360844 I) (-137200. – 16000. dco –
400. dco^2))/(-6560. – 1371. dco – 60. dco^2 – 1. dco^3 +
5.19615 Sqrt[
99259. + 143320. dco + 24722. dco^2 + 1160. dco^3 +
19. dco^4])^(
1/3) – (0.00833333 + 0.0144338 I) (-6560. – 1371. dco –
60. dco^2 – 1. dco^3 +
5.19615 Sqrt[
99259. + 143320. dco + 24722. dco^2 + 1160. dco^3 +
19. dco^4])^(1/3)}, {x ->
0.0333333 (-10. + dco) + ((0.0000208333 +
0.0000360844 I) (-137200. – 16000. dco –
400. dco^2))/(-6560. – 1371. dco – 60. dco^2 – 1. dco^3 +
5.19615 Sqrt[
99259. + 143320. dco + 24722. dco^2 + 1160. dco^3 +
19. dco^4])^(
1/3) – (0.00833333 – 0.0144338 I) (-6560. – 1371. dco –
60. dco^2 – 1. dco^3 +
5.19615 Sqrt[
99259. + 143320. dco + 24722. dco^2 + 1160. dco^3 +
19. dco^4])^(1/3)}, {x ->
0.0333333 (-10. + dco) – (
0.0000416667 (-137200. – 16000. dco – 400. dco^2))/(-6560. –
1371. dco – 60. dco^2 – 1. dco^3 +
5.19615 Sqrt[
99259. + 143320. dco + 24722. dco^2 + 1160. dco^3 +
19. dco^4])^(1/3) +
0.0166667 (-6560. – 1371. dco – 60. dco^2 – 1. dco^3 +
5.19615 Sqrt[
99259. + 143320. dco + 24722. dco^2 + 1160. dco^3 +
19. dco^4])^(1/3)}}
i want my ans in interpolation form.
i think you can help me.

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Recent Questions – Mathematica Stack Exchange

answer, coffecient, Getting, graph, inexact, Long, plot, Result, Without
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